VHDL Assignment #10: Description of Storage Elements and Sequential Circuits in VHDL Solution

In this VHDL assignment, you will first learn how to describe storage elements and sequential logic circuits in VHDL. Then, you will design a 3-bit up-counter and simulate the counter using ModelSim.

    • Learning Outcomes

After completing this lab you should know how to

    • Describe sequential elements in VHDL

    • Design a clock divider circuit

    • Design a 3-bit counter in VHDL

    • Perform functional simulation of the counter using ModelSim

    • Prerequisites

Before starting this lab you should

    • Read Section 7.12.2 of the text book

    • Read Examples 7.10, 7.11, and 7.12 in Section 7.13.3 of the text book

    • Be familiar with the information in previous coding assignments.

If you need any help regarding the lab materials, you can

    • Ask for help from the TA of your lab session

    • Refer to the text book. In case you are not aware, Appendix A “VHDL Reference" provides detailed informa-tion on VHDL.

    • You can also refer to the tutorial on Quartus and ModelSim provided by Intel (click here for Quartus and here for ModelSim).

It is highly recommended that you first try to resolve any issue yourselves by referring to the textbook, Altera Board manual, and/or the multitude of VHDL resources on the Internet. Syntax errors especially can be quickly resolved by reading the error message to see exactly where the error occurred and checking the VHDL Reference or examples in the textbook for the correct syntax.

    • VHDL Description of Storage Elements

In the previous VHDL assignments, you have learned how to use sequential statements to describe the behavior of combinational circuits inside the process block. Sequential statements within the process block can also be used to describe sequential circuits such as storage elements. In digital systems, we have two types of memory elements: latches and flip-flops (FFs). Latches are memory elements that immediately reflect any changes in the input signal to the output signal when the level of the control signal (clk) is high. As such, latches are usually referred to as level-triggered memory elements. Alternatively, FFs change their state when the control signal goes from either


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high to low or from low to high. Note that FFs working with a control signal that goes from high to low or from low to high are called, respectively, negative-edge-triggered and positive-edge-triggered FFs. In digital systems, edge-triggered flip-flops are superior to level-triggered latches since FFs are more robust. For example, noise can easily disrupt the output of a latch when the control signal is high. On the hand, the output of FFs can be disrupted only in presence of noise at the edge transition of the control signal. Tt is highly recommended, therefore, to use FFs when designing sequential circuits.

In VHDL, process blocks are used to describe FFs. Since FFs set their state at the edge of the control signal, we need a statement to detect the edge transition of the control signal. This can be simply done by using a IF-THEN-ELSE statement. Assuming that clk is the control signal of a FF, a positive edge transition (i.e., a transition from ’0’ to ’1’) of the clk signal can be detected by the following statement: RISING_EDGE (clk). Similarly, a negative edge transition (i.e., a transition from ’1’ to ’0’) can be detected by the following statement FALLING_EDGE (clk). For example, the following process block describes a positive-edge-triggered DFF.


PROCESS ( clk )

BEGIN

IF RISING_EDGE( clock ) THEN

Q<=D;

END IF;

END PROCESS;

Since the state Q (output) changes only as a result of a positive clock edge, only the clk signal is listed in the sensitivity list of the process. Note that there are additional ways to detect a clock edge, such as IF clk’EVENT AND clk = ’1’ or WAIT UNTIL clk’EVENT AND clk = ’1’ statements. The syntax clk’EVENT uses a VHDL construct called an attribute. An attribute refers to a property of an object such as a signal. In this case, the ’EVENT attribute refers to any change in the clock signal. These two statements (i.e., clk’EVENT AND clk = ’1’ and WAIT UNTIL clk’EVENT AND clk = ’1’) are described in detail in Examples 7.2 and 7.3 of the textbook. Note that if we use the WAIT UNTIL statement, then the sensitivity list of the process block should be empty.

So far, we have described a positive-triggered flip-flop in VHDL. Now, let us describe a positive-triggered flip-flop with asynchronous active-low reset (also known as clear) and asynchronous active-low set signals. When the reset signal is ’0’, the output of the FF is immediately set to ’0’, regardless of the value of the control signal (i.e., clk). Similarly, when the set signal is ’0’, the output of the FF is immediately set to ’1’, regardless of the value of the control signal (i.e., clk). The sensitivity list of the process contains, therefore, the clk, reset, and set signals, since these three signals trigger a change in the output of the FF (positive clock edge and low-activated set and reset signals. A positive-triggered FF with asynchronous active-low reset and set signals can be described in VHDL as follows:


PROCESS ( clk,  reset,  set )

BEGIN

IF reset = ’0’ THEN

Q <= ’0’;

ELSIF set = ’0’ THEN

Q <= ’1’;

ELSIF RISING_EDGE( clk ) THEN

    • <= D;

END IF;

END PROCESS;

Note that since we check the reset signal first, it has priority over the other two signals, i.e., set and clk. Similarly, set has priority over the clk signal.












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If we check for the reset and set signals at the positive edge of the clock, we obtain a positive-triggered flip-flop with synchronous active-low reset and set signals as follows:


PROCESS ( clk )

BEGIN

IF RISING_EDGE( clk ) THEN

IF reset = ’0’ THEN

Q <= ’0’;

ELSIF set = ’0’ THEN

Q <= ’1’;

ELSE

    • <= D;

END IF;

END IF;

END PROCESS;

Note that we do not include the reset and set signals in the sensitivity list of a flip-flop circuit with synchronous reset and set signals.

    • Design of a Storage Element

In this assignment, you are asked to design a JKFF. The inputs to the FF are J, K, and clk. The output of the

    FF is Q. The operation of a JKFF is described in Lecture 24 and in Section 7.6 in the textbook. Use the following entity declaration for your implementation of the storage element circuit.


library IEEE;

use IEEE.STD_LOGIC_1164.ALL;
use IEEE.NUMERIC_STD.ALL;
entity f i r s t n a m e _ l a s t n a m e _ j k f f  i s

Port ( clk
:  in

std_logic;
J
:
in
std_logic;
K
:
in
std_logic;
Q
:
out std_logic;
end f i r s t n a m e _ l a s t n a m e _ j k f f ;

where firstname_lastname in the name of the entity is the name of one of the students in your group.

To describe your circuit in VHDL, use a single process block. Once you have your circuit described in VHDL, you should simulate it. Write a testbench code and perform a functional simulation for your VHDL description of the counter. When writing a testbench for sequential circuits, a clock signal is required within the testbench. One way to generate the clock signal in testbench, is provided below.


c l o c k _ g e n e r a t i o n :  process

begin

clk <= ’1’;

wait for c l o c k _ p e r i o d /2;

clk <= ’0’;

wait for c l o c k _ p e r i o d /2;
end process c l o c k _ g e n e r a t i o n ;

Note that the “clock_period” parameter should be replaced with desired clock period value. In this assignment, we will use a clock period of 10 ns. Due to the absence of any indefinite “wait” statement in the “clock_generation” process, you cannot use the run -all command in ModelSim; you must instead explicitly determine a simulation duration (e.g., run 100 ns).

Once you have described your circuit in VHDL, you should write a testbench and simulate the circuit in ModelSim.

Make sure that all possible inputs to the JKFF are verified in the simulation.








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    • Counters

A counter is a special sequential circuit. When counting up (by one), we require a circuit capable of “remembering” the current count and increase it by 1 the next time we request a count. When counting down (by one), we require a circuit capable of “remembering” the current count and subtracting 1 the next time we request a count. Counters use a clock signal to keep track of time. In fact, each increment (or decrement) occurs when one clock period has passed. To design an up-counter counting in increments of 1 second, we will first design a 3-bit up-counter counting at positive edge of the clock with an asynchronous reset (which should be active low) and an enable signal (which should be active high). The counter counts up when the enable signal is high. Otherwise, the counter holds its previous value. Use the following entity declaration for your VHDL description of the counter:


library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.NUMERIC_STD.ALL;

entity
f i r s t n a m e _ l a s t n a m e _ c o u n t e r  i s
Port
( enable
:  in
std_logic;

reset
:  in
std_logic;

clk
:  in
std_logic;

count
:  out
std_logic_vector(2  downto 0) ) ;
end f i r s t n a m e _ l a s t n a m e _ c o u n t e r ;

where firstname_lastname in the name of the entity is the name of one of the students in your group.

Note that a 3-bit counter counts from 0 to 7. When the current count reaches 7, the next count will automatically wrap around back to 0.

Once you have your circuit described in VHDL, you should simulate it. Write a testbench code and perform a functional simulation for your VHDL description of the counter.

    • Clock Divider

A clock divider is a circuit that generates a signal that is asserted once every T clock cycles. This signal can be used as a condition to enable the counter that you designed in Section 5. An example of the clock and output (i.e., “enable”) waveforms for T = 4 is:


3    2    1    0    3    2    1    3

Clock





Enable




Implementing the clock divider circuit requires a counter counting clock periods. The counter counts down from T −1 to 0. Upon reaching the count of 0, the clock divider circuit outputs/asserts 1 and the count is reset to T −1. For other values of the counter, the output signal of the clock divider circuit remains 0. In this lab, we want to design a counter counting in increments of 1 second. In other words, we need to assert an enable signal every 1 second. First, find the value of T for the clock divider circuit to generate an enable signal every 1 second. Note that the PLL, the device which supplies the clock for your design on the DE1-SoC board, works at a frequency of 50 MHz, however, since this assignment was converted to a simulation-based assignment, we will use a slower clock to avoid very long simulation time. We will therefore use 10 Hz as the clock frequency for our simulation. Describe the clock divider circuit in VHDL using the following entity declaration:


McGill University    ECSE 222 – Digital Logic (Winter 2020)

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library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.NUMERIC_STD.ALL;

entity f i r s t n a m e _ l a s t n a m e _ c l o c k _ d i v i d e r  i s

Port
( enable
:  in
std_logic;

reset
:  in
std_logic;

clk
:  in
std_logic;
end
en_out
:  out
std_logic) ;

f i r s t n a m e _ l a s t n a m e _ c l o c k _ d i v i d e r ;

where firstname_lastname in the name of the entity is the name of one of the students in your group.

Hint: The following figure shows an example of the clock divider circuit. Also, note that the down-counter inside the clock divider circuit is different from the up-counter that you designed in Section 5, and that en_out is the NOR of the bits in the counter value.



clk


reset
Down Counter
en_out

From T-1 to 0




enable





Once you have your circuit described in VHDL, write a testbench code and perform a functional simulation for your VHDL description of the clock divider.

    • 3-bit Up-Counter Counting in Increments of 1 Second

In this part, you will design a simple counter circuit that counts in increments of 1 second using the counter and clock divider circuits.

Reset is an asynchronous active-low input. The normal condition of the reset is high (’1’). If reset goes low (’0’), the output of the counter should be 0 as long as reset remains low. Once reset goes back high, the counter should start counting. Enable is a synchronous active-high input. When enable is high (’1’) the counter counts every 1 second, the circuit will hold and display the current count otherwise.

You will need to create one instance of your firstname_lastname_counter and seven_segment_decoder you created in VHDL Assignment #6. Since we measure time in increments of 1 second, the counter that you designed in Section 5 increments only when the output signal of the clock divider circuit becomes high. The following figure shows the high-level architecture of the circuit.



















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Describe the circuit counting at every 1 second in VHDL using the following entity declaration:


library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.NUMERIC_STD.ALL;

entity f i r s t n a m e _ l a s t n a m e _ w r a p p e r  i s

Port
( enable
:  in
std_logic;

reset
:  in
std_logic;

clk
:  in
std_logic;
end
HEX0
:  out std_logic_vector (6  downto 0) ) ;

f i r s t n a m e _ l a s t n a m e _ w r a p p e r ;

where firstname_lastname in the name of the entity is the name of one of the students in your group.

You will now write a testbench to verify your circuit using the ModelSim simulation. Generate a simulation that shows the functionality of the counter and the reset and enable inputs. Clearly show on the waveform that the counter counts at 1 second intervals.

    • Deliverables and Grading

Read this section extra carefully!

You are required to submit the following files through myCourses:

    • All design files (.vhd)

    • All schematic files (.bdf)

    • All testbench files (.vht)

Per the VHDL assignments submission policy, please note

    • For partially submitted assignments, i.e., some of the files (design/simulation/report) are missing, the penalty is 25% of the full mark of the assignment.

    • For assignments where all the design/simulation files are missing, i.e., only a report was submitted, the penalty is 50% of the full mark of the assignment.

    • For not submitted assignments, i.e., all files are missing, the penalty is 100% of the full mark of the assignment.




























McGill University    ECSE 222 – Digital Logic (Winter 2020)