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HW #6 Solution




You may solve the problems using your choice of software, state which software package/language(s) you used and provide the code or spreadsheet. There is no submission to TEACH this week.




Shortest Paths using LP: (7 points)



Shortest paths can be cast as an LP using distances dv from the source s to a particular vertex v as variables.




We can compute the shortest path from s to t in a weighted directed graph by solving.



max dt

subject to




ds = 0

dv – du ≤ w(u,v) for all (u,v) E




We can compute the single-source by changing the objective function to
max ∑ ∈




Use linear programming to answer the questions below. State the objective function and constraints for each problem and include a copy of the LP code and output.




Find the distance of the shortest path from G to C in the graph below.



Find the distances of the shortest paths from G to all other vertices.



















2




F


3




5




C








A
10
7


4
3










8












18
4
9


B


D














10












H




2

3




9 25
G E




7










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CS 325 HW 6




Product Mix: (7 points)
Acme Industries produces four types of men’s ties using three types of




material. Your job is to determine how many of each type of tie to make each month. The goal is to maximize profit, profit per tie = selling price - labor cost – material cost. Labor cost is $0.75 per tie for all four types of ties. The material requirements and costs are given below.




Material
Cost per yard






Yards available


















per month








































Silk




$20








1,000












Polyester




$6








2,000












Cotton




$9








1,250


















































Type of Tie






































Product Information


Silk = s


Poly = p




Blend1 = b


Blend2 = c


























Selling Price per tie


$6.70




$3.55




$4.31






$4.81




























Monthly Minimum units


6,000




10,000




13,000






6,000




























Monthly Maximum units


7,000




14,000




16,000






8,500








































































Material














Type of Tie














Silk


Polyester


Blend 1


Blend 2


Information in










yards


















(50/50)




(30/70)


Silk




0.125


0




0




0




Polyester




0


0.08


0.05




0.03


Cotton




0


0




0.05




0.07








Formulate the problem as a linear program with an objective function and all constraints. Determine the optimal solution for the linear program using any software you want. Include a copy of the code and output. What are the optimal numbers of ties of each type to maximize profit?





































2

CS 325 HW 6




Transshipment Model (10 points)



This is an extension of the transportation model. There are now intermediate transshipment points added between the sources (plants) and destinations (retailers). Items being shipped from a Plant (pi) must be shipped to a Warehouse (wj) before being shipped to the Retailer (rk). Each Plant will have an associated supply (si) and each Retailer will have a demand (dk). The number of plants is n, number of warehouses is q and the number of retailers is m. The edges (i,j) from plant (pi)to warehouse (wj) have costs associated denoted cp(i,j). The edges (j,k) from a warehouse (wj)to a retailer (rk) have costs associated denoted cw(j,k).




The graph below shows the transshipment map for a manufacturer of refrigerators. Refrigerators are produced at four plants and then shipped to a warehouse (weekly) before going to the retailer.












R1


R2
P1
W1



R3




P2

W2 R4




P3




R5







W3

P4




R6







R7







Below are the costs of shipping from a plant to a warehouse and then a warehouse to a retailer. If it is impossible to ship between the two locations an X is placed in the table.




cost
W1
W2
W3
P1
$10
$15
X
P2
$11
$8
X
P3
$13
$8
$9
P4
X
$14
$8



3

CS 325 HW 6










cost
R1
R2
R3
R4
R5
R6
R7
W1
$5
$6
$7
$10
X
X
X
W2
X
X
$12
$8
$10
$14
X
W3
X
X
X
$14
$12
$12
$6






The tables below give the capacity of each plant (supply) and the demand for each retailer (per week).












P1


P2


P3


P4






















Supply




150




450




250




150
















































































R1




R2






R3




R4




R5


R6


R7


Demand




100






150








100






200






200




150




100








Part A: Determine the number of refrigerators to be shipped from the plants to the warehouses and then warehouses to retailers to minimize the cost. Formulate the problem as a linear program with an objective function and all constraints. Determine the optimal solution for the linear program using any software you want. What are the optimal shipping routes and minimum cost?




Part B: Due to old infrastructure Warehouse 2 is going to close eliminating all of the associated routes. What is the optimal solution for this modified model? Is it feasible to ship all the refrigerators to either warehouse 1 or 3 and then to the retailers without using warehouse 2? Why or why not?




Part C: Instead of closing Warehouse 2 management has decide to keep a portion of it open but limit shipments to 100 refrigerators per week. Is this feasible? If so what is the optimal solution when warehouse 2 is limited to 100 refrigerators?




Note: Include a copy of the code for all parts of the problem.




Making Change (6 points)



Given coins of denominations (value) 1 = v1 < v2< … < vn, we wish to make change for an amount A using as few coins as possible. Assume that vi’s and A are integers. Since v1= 1 there will always be a solution. Solve the coin change using integer programming. For each the following denomination sets and amounts formulate the problem as an integer program with an objective function and constraints, determine the optimal solution. What is the minimum number of coins used in each case and how many of each coin is used? Include a copy of your code.




V = [1, 5, 10, 25] and A = 202.



V = [1, 3, 7, 12, 27] and A = 293
















































































































































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