1. One Binary Number
Write a function with this prototype:
void binary_print(ostream& outs, unsigned int n);
The function prints the value of n as a BINARY number to the ostream outs. If n is zero, then a single zero is printed; otherwise no leading zeros are printed in the output. The '\n' character is NOT printed at the end of the output.
EXAMPLES:
n=0 Output:0
n=4 Output:100
n=27 Output:11011
NOTE: Your recursive implementation must not use any local variables.
2. Triangle Pattern
void triangle(ostream& outs, unsigned int m, unsigned int n)
// Precondition: m <= n
// Postcondition: The function has printed a pattern of 2*(n-m+1) lines
// to the output stream outs. The first line contains m asterisks, the next
// line contains m+1 asterisks, and so on up to a line with n asterisks.
// Then the pattern is repeated backwards, going n back down to m.
/* Example output:
triangle(cout, 3, 5) will print this to cout:
***
****
*****
*****
****
***
*/
Hint: Only one of the arguments changes in the recursive call. Which one?
3. Pow Function (Project 13, page 452)
Rewrite the recursive pow function from Fig. 9.10 on page 445, so that the time to compute pow(x,n) is log(n):
double pow(double x, int n);
// Precondition: If x is zero, then n must be positive.
// Postcondition: The value returned is x raised to the power n.
Hint: use the formula x^2n = x^n x^n
4. Repeated and Indented Sentences (Project 1, page 450)
Write a function that produces output like the following:
This was written by calling number 1.
This was written by calling number 2.
This was written by calling number 3.
This was written by calling number 4.
This was ALSO written by calling number 4.
This was ALSO written by calling number 3.
This was ALSO written by calling number 2.
This was ALSO written by calling number 1.
In the above example, the recursion stopped when it reached four levels deep, but your function should be capable of continuing any specific level with the following function prototype.
void indented_sentences(size_t m, size_t n);
// precondition: m <=n;
//postcondition: print out the above pattern by calling number from m to n
