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Final Question 1: Grab Bag Solution




Prove that the function f(x) = (8x + 5) mod 17 is injective on the set f0; 1; 2; 3; : : : ; 15; 16g (10 points).



Is f(x) = (8x + 5) mod 17 invertible on this set? If so, give its inverse function (5 points).



Is f(x) = (8x + 5) mod 18 invertible on this set? If so, give its inverse function (5 points).



True or false - give a mathematical justi cation (10 points):



a) n = O(n2).




b) n(n + 1)(n + 2)
n3
= O(n3).
c) n(n + 1)(n + 2)
n3
= O(n2).



n ln n = O(n2).



n2 = O(n ln n).



1=n = O(1).



1000000n = O(n).



2n = O(3n).



3n = O(2n).


P
n
j)
i=1 i(i + 1)(i + 2) = O(n4).
The ‘double factorial’ is a variant on the factorial function where every other number is multiplied together:



for instance, 9!! = 9 7 5 3 1 = 945, 10!! = 10 8 6 4 2 = 3840. In general, n!! is much smaller than n! (20 points).




{ Argue that n!!=n! goes to 0 as n ! 1, i.e., n! dominates n!! severely. Hint: Be wary of cases.




{ Argue, however, that in the limit for even n, ln(n!!)=(n ln n) is bound from above and below by some constants.




{ Argue that for odd n, ln(n!!)=(n ln n) is bound from above and below by some constants as well. Hint:




Show that n! = n!!(n 1)!!.




{ Conclude therefore that while n! is a lot larger than n!!, we have that ln n!! = (ln n!).



































































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