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Homework 3 Solution




Suppose that you are given the bitmap representation of a set S of non-negative integers. Describe how to find the smallest non-negative integer x that is not a member of S, in a constant number of integer operations.



(This is an important operation in combinatorial game theory, where it is called the “minimum excluded value” or “mex”. You may assume that the dictionary set2element from the lecture notes has already been computed and that looking up a key-value pair in that dictionary is allowed among the constant number of operations that you perform. You may also assume that the resulting value x is within the range of values allowed by your bitmap set representation.)















The lecture notes provide formulas that, for bitmap-based sets, perform the operations of set union, set intersection, and testing whether one set is a subset of another. Which of these formulas work correctly without modification on Bloom filters? (You can assume that the Bloom filter is small enough to fit into a single word of memory, so that the same formulas can be used; the question is about the correctness of these formulas, not about their implementation.) Explain your answers.














We have seen that, to achieve a false positive rate of " for a set of n items, Bloom filters need
(n log2 1/")/ log 2 bits of storage. We didn’t analyze cuckoo filters as precisely, but many sources give a bound of n(2 + log2 1/") on the number of bits of storage needed for them. Assuming that this bound is accurate, for which values of " do cuckoo filters use fewer bits than Bloom filters, and for which values of




do cuckoo filters use more bits? (It may be easiest to solve this numerically by writing a short computer program.)














The lectures for this week include a proof that, if the strong exponential time hypothesis (SETH) is true, then for every constant " 0 the disjointness data structure problem for N sets of size k cannot be solved with preprocessing time N2−"kO(1) and query time N1−"kO(1). Prove a stronger bound on the preprocessing, with the same bound on the query time: if SETH is true, then for every two constants a 0 and " 0, the disjoint set data structure problem cannot be solved with preprocessing time NakO(1) and query time N1−"kO(1).



Hint: Follow the same proof strategy as in the lecture notes, but partition the variables of the satisfiability instance into two subsets of unbalanced sizes, depending on a. Which collection of partial truth assignments should be used as the data for the disjointness structure, and which collection of partial truth assignments should be used as the queries?



























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