Programming Assignment 5 Minimum Spanning Tree (MST) Solution

In this assignment, you will implement Tarjan and Cheriton's round‐robin algorithm for finding the minimum spanning tree of a weighted undirected graph.




Note: This assignment challenges you to (a) understand a non‐trivial algorithm, and (b) match the algorithm to code. It may take a couple of readings of the entire algorithm description and the given code template before you see how all the pieces connect. Draw pictures of data structures for better understanding!!










You will work on this assignment individually. Read DCS Academic Integrity Policy for Programming Assignments ‐ you are responsible for abiding by the policy. In particular, note that "All Violations of the Academic Integrity Policy will be reported by the instructor to the appropriate Dean".










IMPORTANT ‐ READ THE FOLLOWING CAREFULLY!!!




Assignments emailed to the instructor or TAs will be ignored‐‐they will NOT be accepted for grading. We will only grade submissions in Sakai.




If your program does not compile, you will not get any credit.







Most compilation errors occur for two reasons:




You are programming outside Eclipse, and you delete the "package" statement at the top of the file. If you do this, you are changing the program structure, and it will not compile when we test it.
You make some last minute changes, and submit without compiling.



To avoid these issues, (a) START EARLY, and give yourself plenty of time to work through the assignment, and (b) Submit a version well before the deadline so there is at least something in Sakai for us to grade. And you can keep submitting later versions (up to 10) ‐ we will accept the LATEST version.




A separate Sakai assignment will be opened for extensions AFTER the deadline for the regular submission has passed.










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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




Minimum Spanning Tree




Round‐robin MST Algorithm




Implementation




Running the Program




Submission










Minimum Spanning Tree




Several real‐world problems need to find a so‐called minimum spanning tree (MST) in an undirected graph with positive edge weights.




In an undirected graph, any subset of the vertices and edges that does not contain any cycles is a tree. A spanning tree is a tree that connects every vertex of the graph. If the graph has weighted edges, a minimum spanning tree is one for which the sum of the weights of the tree edges is minimized, i.e. the edge weights sum is no more than that for any other spanning tree. (Multiple minimum spanning trees are possible for a graph.)




The following is an example of weighted undirected graph, stored in file graph1.txt

















































Here are a couple of spanning trees that can be computed on this graph:

















































The sum of the edge weights for this spanning tree is 54 The sum of the edge weights for this spanning tree is 37













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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




Round‐robin MST Algorithm




A partial spanning tree is a tree that spans only a subset of a graph (only some of the vertices in the graph are connected by the partial tree). In Tarjan and Cheriton's round‐robin algorithm, partial trees are built and combined until only one remains: the MST of the entire graph.




Following is the algorithm, which is illustrated using this graph, stored in file graph2.txt














































There are 9 steps in the following algorithm, followed by some notes. Read the whole thing (all steps plus notes) carefully and repeatedly until you get it (draw pictures as needed!). After getting a reasonably good understanding of the algorithm, read over the code template you are given so you can map the algorithm to the implementation, and fill in any blanks in your understanding.




Create an empty list L of partial trees.



Separately for each vertex v in the graph:



Create a partial tree T containing only v.
Mark v as belonging to T (this will be implemented in a particular way in the code).
Create a priority queue (heap) P and associate it with T.
Insert all of the arcs (edges) connected to v into P. The lower the weight on an arc, the higher its priority.
Add the partial tree T to the list L.



We will represent a partial tree like this:




Ve ices: [list of ve ices, root rst] PQ: [arcs in priority order]




At the end of step 2, we have the following list, L, of partial trees:




T1. Ve ices: A PQ: (A C 1), (A D 3), (A B 4)




T2. Ve ices: B PQ: (B D 3), (B A 4), (B C 5)




T3. Ve ices: C PQ: (C A 1), (C E 2), (C D 4), (C B 5)




T4. Ve ices: D PQ: (D E 1), (D A 3), (D B 3), (D C 4)




T5. Ve ices: E PQ: (E D 1), (E C 2)




Note:




Every partial tree has one vertex designated as its "root".







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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




The PQ representation above lists arcs in a sorted order of arc weights (priorities), ONLY to show that that if the arcs were to be removed







one at a time, they would follow the listed order. The actual ordering of arcs in the heap will be different since the heap implements only a partial order on its items.




The initial ordering of partial trees in list L is arbitrary.







3. Remove the first partial tree PTX from L. Let PQX be PTX's priority queue.




T1. Ve ices: A P1: (A C 1), (A D 3), (A B 4)




4. Remove the highest‐priority arc from PQX. Say this arc is α. Let v1 and v2 be the two vertices connected by α, where v1 belongs to PTX.




α: (A C 1) v1: A v2: C




5. If v2 also belongs to PTX, go back to Step 4 and pick the next highest priority arc, otherwise continue to the next step.




C belongs to a di erent pa ial tree (T3) than A, continue to the next step.




Report α ‐ this is a component of the minimum spanning tree.



(A C 1) is a component of the MST




Find the partial tree PTY to which v2 belongs. Remove PTY from the partial tree list L. Let PQY be PTY's priority queue.



T3. Ve ices: C PQ: (C A 1), (C E 2), (C D 4), (C B 5)




Combine PTX and PTY. This includes merging the priority queues PQX and PQY into a single priority queue. Append the resulting tree to the end of L.



T2. Ve
ices: B PQ: (B D 3), (B A 4), (B C 5)
T4. Ve
ices: D PQ: (D E 1), (D A 3), (D B 3), (D C 4)
T5. Ve
ices: E PQ: (E D 1), (E C 2)
T13. Ve
ices: A C PQ: (C A 1), (C E 2), (A D 3), (A B 4), (C D 4), (C B 5)



If there is more than one tree in L, go to Step 3. Notes:
Arc (x y) is the same as arc (y x).




A partial tree is labeled (identified) by its "root" vertex. This vertex is not really special ‐ it is simply the first vertex that was added to the tree.




We can use this label to tell whether or not two given vertices belong to the same tree.




Each vertex keeps a pointer to its "parent" in the partial tree. The parent is just some other vertex in the tree ‐ there isn't necessarily an edge connecting a vertex to its parent. From a given vertex, we can follow the chain of parent pointers all the way up to the root (vertex) of the partial tree to which the vertex belongs. If two vertices have the same root they are in the same tree, and if they have different roots they are in different trees.







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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




When merging one partial tree (say PTY) into another (say PTX), we have to change the root of all of PTY's vertices to the root of PTX. We can do this easily by setting the parent pointer of the root of PTY to point to the root of PTX: any vertex which used to be in PTY will now have PTX's root as its root.







Continuing to trace the algorithm on the example, after the first iteration there are still four partial trees in the list. So we repeat the process from Step 3 on. The next partial tree to be removed is T2, and its highest priority arc is (B D 3). Since D is in a different partial tree (T4) than T2, the partial




trees T2 and T4 are combined, and the list is updated to the following:




T5. Ve ices: E PQ: (E D 1), (E C 2)




T13. Ve ices: A C PQ: (C A 1), (C E 2), (A D 3), (A B 4), (C D 4), (C B 5)




T24. Ve ices: B D PQ: (D E 1), (D A 3), (D B 3), (B A 4), (D C 4), (B C 5)




Repeating again, the next partial tree to be removed is T5, and its highest priority arc is (E D 1). Since D is in a different partial tree (T24) than T5, the partial trees T5 and T24 are combined, and the list is updated to the following:




T13. Ve ices: A C PQ: (C A 1), (C E 2), (A D 3), (A B 4), (C D 4), (C B 5)




T524. Ve ices: E B D PQ: (D E 1), (E C 2), (D A 3), (D B 3), (B A 4), (D C 4), (B C 5)




Repeating again, the next partial tree to be removed is T13, and its highest priority arc is (C A 1). However, C and A belong to the same partial tree, we discard this arc (Step 5) and return to Step 4, to pick the next highest priority arc. This is (C E 2). Since E is in a different partial tree (T524) than T13, the partial trees T13 and T524 are combined, and the list is updated to the following:




T13524. Ve ices: A C E B D PQ: (D E 1), (E C 2), (A D 3), (D A 3), (D B 3), (A B 4), (C D 4), (B A 4), (D C 4), (C B 5), (B C 5)




Notice that when combining the priority queues, several arcs appear in duplicate (e.g. (A D 3) and (D A 3), etc.) in the combined priority queue, even




though they are the same arc. This is ok, it will not effect the correctness of the algorithm. (In other words, there is no need to check whether the priority queues to be combined have common arcs.)




Now that there is only one tree left, we are done. The set of arcs we used to combine the partial trees is the MST of the graph:



















A C 1




B D 3




E D 1




C E 2
















Note: The sequence in which arcs are added to the MST is irrelevant.













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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




Implementation




Download the attached mst_project.zip file to your computer. DO NOT unzip it. Instead, follow the instructions on the Eclipse page under the section "Importing a Zipped Project into Eclipse" to get the entire project into your Eclipse workspace.




You will see a project called MST with the following classes:




structures.Ve ex (with inner class Neighbor)







structures.Graph







structures.MinHeap







apps.Pa ialTree (with inner class Arc)







apps.Pa ialTreeList







apps.MST







The project also includes the graph1.txt and graph2.txt files used in the description of the algorithm in the Minimum Spanning Tree section.




Fill in the following methods where indicated in the Pa ialTreeList.java and MST.java files:









Method
Points




MST: initialize
20
Pa
ialTreeList: remove
10
Pa
ialTreeList: removeTreeContaining
25
MST: execute
20



The ONLY changes you are allowed to make in any of the given files are the following:




Fill in the implementations of the required methods.




Add private helper methods in the Pa ialTreeList and MST classes.










Running the Program




You need to write your own driver program to create a Graph object from an input graph file, and call the MST methods to run the algorithm on this graph.




For all the test cases you build, create test files like graph2.txt and place them in the same folder as graph2.txt




Note: The Pa ialTree class toString method returns a string that shows a single (root) vertex and a list of arcs in the priority queue. This is different from the illustration of the algorithm. So, for instance, the illustration had this after the first merge of step 8, for the tree T13:







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11/22/2016 CS112 Fall 2016 ­ Minimum Spanning Tree




Ve ices: A C PQ: (C A 1), (C E 2), (A D 3), (A B 4), (C D 4), (C B 5)




But the Pa ialTree class toString method will show this:







Ve ices: A PQ: (C A 1) (C E 2) (A D 3) (A B 4) (C B 5) (C D 4)




(The A vertex is shown because it is the root. The C vertex is not shown.)







Submission




Submit your Pa ialTreeList.java and MST.java files as two separate files, NOT as a single zip file.



















































































































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