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STAT 3250 Assignment 1, Part A

For the questions in this part, use the following

lists as needed:

mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]

mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]




A1. Find the last four digits of the 13th Mersenne

prime, which is equal to 2^521 - 1.




A2. Find the product of the 7th entry in mylist01,

the 13th entry in mylist01, and the 4th entry

in mylist02.




A3. Extract the sublist of mylist02 that goes from

the 5th to the 9th elements (inclusive).




A4. Concatenate mylist01 to mylist02, sort the new

combined list, then extract the sublist that 

goes from the 8th to the 19th elements (inclusive).




A5. Determine the number of times 8 appears in the 

combined list in A4.




A6. Create a new list be removing all of the 3's from

mylist01.




A7. Extract a sublist of mylist02 consisting of every

3rd entry, starting at the end and going in 

reverse.




A8. From the combined list in A4, extract a sublist of

every 5th entry, starting with the 3rd entry.




%%




Assignment 1, Part B

 

For the questions in this part, use the following

lists as needed:

mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]

mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]




B1. Use a for loop to add up the cubes of the entries

of mylist01.




B2. Use a for loop to create mylist03, which has 15

entries, each the product of the corresponding 

entry from mylist01 multiplied by the corresponding

entry from mylist02. That is,

mylist03[i] = mylist01[i]*mylist02[i] 

for each 0 <= i <= 14.




B3. Use a for loop to compute the mean of the entries

of mylist02. (Hint: len(mylist02) gives the number

of entries in mylist. This is potentially useful.)







%%




Assignment 1, Part C

 

For the questions in this part, use the following

lists as needed:

mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]

mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]

mylist03 = [2,-5,6,7,-2,-3,0,3,0,2,8,7,9,2,0,-2,5,5,6]

biglist = mylist01 + mylist02 + mylist03




C1. Use a for loop to determine the number of entries

in "biglist" that are greater than 4.




C2. Use a for loop to determine the number of entries

in "biglist" that are between -1 and 3 (inclusive).




C3. Create a new list called "mylist04" that contains 

the elements of biglist that are not divisible by 3.







%%























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